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[2001-10-23 14:21 UTC] robert dot w at 12move dot nl
Quoting the fifth paragraph of the English language version: "Unlike include(), require() will always read in the target file, even if the line it's on never executes. If you want to conditionally include a file, use include(). The conditional statement won't affect the require(). However, if the line on which the require() occurs is not executed, neither will any of the code in the target file be executed." I think the last line is contradicting the first line : FIRST LINE : "...require() will always read in the target file, even if the line it's on never executes." LAST LINE : "However, if the line on which the require() occurs is not executed, neither will any of the code in the target file be executed." This the same in the Dutch language version. IMHO the last line should read : "However, if the line on which the include() occurs is not executed, neither will any of the code in the target file be executed." Robert Waarde PatchesPull RequestsHistoryAllCommentsChangesGit/SVN commits
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To Robert: It means that the file is included there, but the code from the file is not executed, because some condition (eg. an if statement). if ($foo) { require "foo.php"; } This code (as the manual says) will __always__ load in foo.php and will replace the require statement with the contents of that file, but this content is only executed if $foo is true. Goba