no. it will echo contents of $three. if you don't have that variable in current scope, it'll echo null, and, depending on your settings, emit a warning.

ok and that isn;t working either...
althoug i liked the first more (and still think it should be that way)

so this doesn't work either:

$three = "Grrrr";

echo "Test";
$test = Array("one","two","three","four"); $var = 'test[2]'; echo $$var; /* should echo "three" */

changed status

ah, sorry, should've read the report more carefully.

It is definitely not meant to work this way. 'test[2]' is
not a variable name. $test is the variable (array), and
$test[2] is second element of the array. So it belongs to
feature requests.

you need to use eval() to make something like this unambiguous.