php.net |  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login
Bug #80855 FILTER_VALIDATE_DOMAIN does not recognize emoji TLDs with FILTER_FLAG_HOSTNAME
Submitted: 2021-03-11 19:54 UTC Modified: 2021-03-11 20:32 UTC
From: vijaycs85 at gmail dot com Assigned:
Status: Not a bug Package: Filter related
PHP Version: 7.4.16 OS: OSX
Private report: No CVE-ID: None
Welcome back! If you're the original bug submitter, here's where you can edit the bug or add additional notes.
If you forgot your password, you can retrieve your password here.
Password:
Status:
Package:
Bug Type:
Summary:
From: vijaycs85 at gmail dot com
New email:
PHP Version: OS:

 

 [2021-03-11 19:54 UTC] vijaycs85 at gmail dot com
Description:
------------
There are some countries that allow Top Level Domains(TLDs) with emoji and the filter_var does not recognize them.

Reference:
https://tinyprojects.dev/projects/mailoji

Test script:
---------------
$domain_name = '⚡.kz';
$is_valid = filter_var($domain_name, FILTER_VALIDATE_DOMAIN, FILTER_FLAG_HOSTNAME);
var_dump($is_valid);

Expected result:
----------------
string(4) "⚡.kz"

Actual result:
--------------
bool(false)

Patches

Pull Requests

History

AllCommentsChangesGit/SVN commitsRelated reports
 [2021-03-11 20:10 UTC] requinix@php.net
-Status: Open +Status: Not a bug
 [2021-03-11 20:10 UTC] requinix@php.net
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

https://www.php.net/manual/en/filter.filters.validate.php
> Optional flag FILTER_FLAG_HOSTNAME adds ability to specifically validate
> hostnames (they must start with an alphanumeric character and contain only
> alphanumerics or hyphens).

Note that ⚡.kz must be converted to punycode, ie. xn--57h.kz. That would be considered valid with the HOSTNAME flag.
 [2021-03-11 20:22 UTC] vijaycs85 at gmail dot com
>Note that ⚡.kz must be converted to punycode, ie. xn--57h.kz. That would be considered valid with the HOSTNAME flag.

Thanks for your quick reply and clarification.
 [2021-03-11 20:29 UTC] vijaycs85 at gmail dot com
Just for future reference, the below code provides the expected result.

$domain_name = '⚡.kz';
$is_valid = filter_var(idn_to_ascii($domain_name), FILTER_VALIDATE_DOMAIN, FILTER_FLAG_HOSTNAME);
var_dump($is_valid);

Output

string(10) "xn--57h.kz"
 [2021-03-11 20:32 UTC] requinix@php.net
Or don't use the HOSTNAME flag.

$domain_name = '⚡.kz';
$is_valid = filter_var($domain_name, FILTER_VALIDATE_DOMAIN);
 
PHP Copyright © 2001-2024 The PHP Group
All rights reserved.
Last updated: Sat Dec 21 15:01:29 2024 UTC