Description:
------------
(int](PHP_MAX_INT + 1) returns \PHP_INT_MIN.
Increasing the argument passed, zero result can be achieved.

Same goes for the \intval() function.

This happens for all current PHP versions - reported by https://3v4l.org/iDnt4

7.2.0 - 7.2.33, 7.3.0 - 7.3.21, 7.4.0 - 7.4.9
8.0.0alpha1 - beta1



Test script:
---------------
<?php

echo '---- INTMAX vs INTMAX+1'. \PHP_EOL;
var_dump(\PHP_INT_MAX);
var_dump(\PHP_INT_MAX+1);
echo '---- INTMAX to float and back'. \PHP_EOL;
var_dump(\intval((float)\PHP_INT_MAX));
var_dump((int)((float)\PHP_INT_MAX));
echo '---- INTMAX+1 to float and back'. \PHP_EOL;
var_dump(\intval(\PHP_INT_MAX+1));
var_dump((int)(\PHP_INT_MAX+1));
var_dump(\PHP_INT_MIN);
echo '---- ...rendezvous point is...'. \PHP_EOL;
var_dump(\intval(18446744073709551615));

Expected result:
----------------
one of:
- \PHP_MAX_INT (just as the documentation states), a sign stable result
- type error
- zero

Actual result:
--------------
overflow or the arithmetical unit