When placed inside a switch statement located inside a for
loop, the continue doesn't work as usual in C:

the following code display the following output:

<?
	for ( $i=0; $i<10; $i++ ) {
		switch ( $i ) {
		case 5:	continue;
		default:
			echo "$i<br>";
		}
		echo "Should be printed only if i != 5 and now i == $i<br>";
	}
?>

//output:

0
Should be printed only if i != 5 and now i == 0
1
Should be printed only if i != 5 and now i == 1
2
Should be printed only if i != 5 and now i == 2
3
Should be printed only if i != 5 and now i == 3
4
Should be printed only if i != 5 and now i == 4
Should be printed only if i != 5 and now i == 5
6
Should be printed only if i != 5 and now i == 6
7
Should be printed only if i != 5 and now i == 7
8
Should be printed only if i != 5 and now i == 8
9
Should be printed only if i != 5 and now i == 9

// End of output

The line :
Should be printed only if i != 5 and now i == 5
should not appear