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Bug #70608 Echo dosn't print false
Submitted: 2015-09-30 12:48 UTC Modified: 2015-09-30 12:58 UTC
From: khaweronline at gmail dot com Assigned:
Status: Not a bug Package: *General Issues
PHP Version: 5.6.13 OS: ALL OS
Private report: No CVE-ID: None
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 [2015-09-30 12:48 UTC] khaweronline at gmail dot com 
Description:
------------
<?php

$a = 12;
$b = 15;

echo $a==$b; // This should output false or 0, but it didn't output anything
var_dump($a==$b); /* This will output Boolean false. This is just for reference that the value is false */

// We can also assign it to a variable then echo and var_dump
$c = $a==$b;

echo $c; // This should output false or 0, but it didn't output anything
var_dump($c); /* This will output Boolean false. This is just for reference that the value is false */

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 [2015-09-30 12:58 UTC] bwoebi@php.net
-Status: Open +Status: Not a bug
 [2015-09-30 12:58 UTC] bwoebi@php.net 
var_dump((string) false);
prints string(0) "", as the string representation of false is actually an empty string.

Hence echoing it actually prints nothing.
 [2015-09-30 12:59 UTC] php at sogetthis dot com 
From the documentation: "A boolean TRUE value is converted to the string "1". Boolean FALSE is converted to "" (the empty string)."

http://php.net/manual/en/language.types.string.php#language.types.string.casting

You could do:
echo $a == $b ? '1' : '0';
 
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