Description:
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---
From manual page: http://www.php.net/types.comparisons
---

2 == '2b'

I understand why, in a loosely typed language, 2 == '2', but it doesn't make sense for an integer to be equal-equal to a string that simply begins with an integer, such as 2 == '2b', so this looks like a bug to me. Rather than casting the string to an integer (i.e., intval('2b') == 2), the integer should cast to a string for the comparison (i.e., strval(2) != '2b'). 

Tested in PHP 5.2.5 and 5.3.13.



Test script:
---------------
<?php

// this is the problem, which we'd expect 
// to return false, but which returns true:
echo (2 == '2b').'<br />';

// this is probably what's happening:
echo (2 == intval('2b')).'<br />';

// this is what probably should happen:
echo (strval(2) != '2b').'<br />';

?>