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Bug #62 s/printf() problem with %% in format string
Submitted: 1998-02-12 01:31 UTC Modified: 1998-02-13 11:54 UTC
From: walton at nordicdms dot com Assigned:
Status: Closed Package: Other
PHP Version: 3.0b4 OS: WinNT
Private report: No CVE-ID: None
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From: walton at nordicdms dot com
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 [1998-02-12 01:31 UTC] walton at nordicdms dot com 
%% appears to steal an argument from the s/printf()
argument list.  When %% is the last %-construct in the
format string, the lack of an argument is silently ignored.
In other cases, unpleasant things happen:

printf("%d %%",1);
1 %

printf("%d %% %d",1,2);
Warning:  sprintf: too few arguments

printf("%d %% %d",1,2,3);
1 % 3

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AllCommentsChangesGit/SVN commitsRelated reports
 [1998-02-13 11:54 UTC] zeev 
Fixed by Stig
 [2023-09-23 18:29 UTC] git@php.net 
Automatic comment on behalf of julionc
Revision: https://github.com/php/doc-es/commit/ffffb45a4341f0ccf8cef220a365ce260388a088
Log: Update recommended.xml
 
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