Description:
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PHP fails to create a zip file when opening an output stream (as detailed on http://www.php.net/manual/en/wrappers.php.php ) rather than a fixed file. The object fails with a ZIPARCHIVE::ER_TMPOPEN on the close method.

I'm guessing - with my rusty C knowledge - this is due to the fact that there's no directory info passed along to create the temporary file in the following source line:

snprintf(temp, len, "%s.XXXXXX", za->zn);
(zip_close.c, 537)

However, attempts to set wide permissions on the current directory (the one the script resides in) or playing with chdir() have not solved the issue.

Reproduce code:
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$sStr = "Test string";
$sFileName = "textfile.txt";

$rZip = new ZipArchive();
$rZip->open("php://temp/maxmemory:".(5 * 1024 * 1024), ZIPARCHIVE::CREATE);
//$rZip->open("/tmp/temp.zip", ZIPARCHIVE::CREATE);
$rZip->addFromString($sFileName, $sStr);
$rZip->close();

print_r($rZip);


Expected result:
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When I run the script with the fixed file name ('/tmp/temp.zip') the output of the print_r is as follows:

ZipArchive Object ( [status] => 0 [statusSys] => 0 [numFiles] => 0 [filename] => [comment] => )

The file is created properly.

Actual result:
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When I run the script with the stream, the stream remains empty (no file is present afterwards) and the print_r gives:

ZipArchive Object ( [status] => 12 [statusSys] => 2 [numFiles] => 1 [filename] => [comment] => )