php.net |  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login

go to bug id or search bugs for

Bug #551 Odd if-else parsing error
Submitted: 1998-07-14 08:29 UTC Modified: 1998-07-14 18:20 UTC
From: mlemos at acm dot org Assigned: zeev (profile)
Status: Closed Package: Parser error
PHP Version: 3.0 Final Release OS: Amiga OS 3.1
Private report: No CVE-ID: None
View Developer Edit
Welcome back! If you're the original bug submitter, here's where you can edit the bug or add additional notes.
If you forgot your password, you can retrieve your password here.
Password:
Status:
Package:
Bug Type:
Summary:
From: mlemos at acm dot org
New email:
PHP Version: OS:

 

 [1998-07-14 08:29 UTC] mlemos at acm dot org 
How come this gives a parsing error,

$locale="en";
 
if($locale!="")
{
 if(file_exists("locale-$locale.php"))
  include("locale-$locale.php");
 else
  $bugs_debug("The include file for locale \"$locale\" does not exist!\n");
}

and this doesn't?

$locale="en";
 
if($locale!="")
{
 if(file_exists("locale-$locale.php"))
 {
  include("locale-$locale.php");
 }
 else
  $bugs_debug("The include file for locale \"$locale\" does not exist!\n");
}

Patches

Pull Requests

History

AllCommentsChangesGit/SVN commitsRelated reports
 [1998-07-14 18:20 UTC] zeev 
This is a known behavior.  The reason is that right now
include and require are *identical* to actually replacing
them with the contents of the file they're including.
So, if that file includes more than one statement, the
script becomes

if (...)
   stmt1
   stmt2
   ...
else
   ...

which is not valid.

Use curly brackets around include, require and eval statements.
 
PHP Copyright © 2001-2024 The PHP Group
All rights reserved. 		Last updated: Sat Dec 21 16:01:28 2024 UTC