php.net |  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login

go to bug id or search bugs for

Bug #54616 in_array return true if the haystack contain 0
Submitted: 2011-04-27 23:45 UTC Modified: 2011-04-28 00:18 UTC
From: kozo at alphanet dot ro Assigned:
Status: Not a bug Package: Unknown/Other Function
PHP Version: 5.2.17 OS: win, linux
Private report: No CVE-ID: None
View Developer Edit
Welcome back! If you're the original bug submitter, here's where you can edit the bug or add additional notes.
If you forgot your password, you can retrieve your password here.
Password:
Status:
Package:
Bug Type:
Summary:
From: kozo at alphanet dot ro
New email:
PHP Version: OS:

 

 [2011-04-27 23:45 UTC] kozo at alphanet dot ro 
Description:
------------
The in_array function return true if the haystack have an element with value 0

Test script:
---------------
if (in_array('something', array(0)) ) {
	echo 'something is in array';
} else {
	echo 'something is NOT in array';
}


if (in_array('something', array(0, 'element1', 'element2')) ) {
	echo 'something is in array';
} else {
	echo 'something is NOT in array';
}


Expected result:
----------------
something is NOT in array

Actual result:
--------------
something is in array

Patches

Pull Requests

History

AllCommentsChangesGit/SVN commitsRelated reports
 [2011-04-28 00:18 UTC] rasmus@php.net
-Status: Open +Status: Bogus
 [2011-04-28 00:18 UTC] rasmus@php.net 
That's what the 3rd param to the in_array() call is for. 
You are looking for a string in an array of integers. 
(int)'something' == 0 and 0 exists in the array. If you
want a strict check that does a type check as well, set
the strict flag. No bug here.
 
PHP Copyright © 2001-2025 The PHP Group
All rights reserved. 		Last updated: Thu Jul 17 14:04:04 2025 UTC