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Bug #540 argv and argc problems
Submitted: 1998-07-11 20:23 UTC Modified: 1998-07-11 21:10 UTC
Votes:1
Avg. Score:5.0 ± 0.0
Reproduced:0 of 1 (0.0%)
From: ben dot lavender at cygnet dot co dot uk Assigned:
Status: Closed Package: Misbehaving function
PHP Version: 3.0 Final Release OS: NT4 SP3
Private report: No CVE-ID: None
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From: ben dot lavender at cygnet dot co dot uk
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 [1998-07-11 20:23 UTC] ben dot lavender at cygnet dot co dot uk 
How can I test argc in an if statement? 

if ( argv > 0)
{
    echo ("there are args");
}

this always fails.

[3] Once I have run
Calling hello.php?a=world&b=tree

parse_str($argv[0]);
if ( ! (isset($a) && isset($b)) )
{
    echo ("failure");
}

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 [1998-07-11 21:10 UTC] rasmus 
if($argc > 0) {
  echo "There are args";
}
But why do you call parse_str() yourself?  In your hello.php example the $a and $b variables will automatically be set by PHP.  You do not need to run parse_str()
(By the way, this is not a bug.  Questions should be sent to php3@lists.php.net)
 
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