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Bug #50493 Terminator and Variable
Submitted: 2009-12-16 14:12 UTC Modified: 2009-12-16 15:00 UTC
From: v dot srinath dot php at gmail dot com Assigned:
Status: Not a bug Package: *General Issues
PHP Version: 5.2.11 OS: Windows
Private report: No CVE-ID: None
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 [2009-12-16 14:12 UTC] v dot srinath dot php at gmail dot com 
Description:
------------
<?php
s
?>
output: nothing appears on browser.
<?php echo $row['column'];s?> 
doesn't show any error.
Is this code acceptable in php?

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 [2009-12-16 14:21 UTC] jani@php.net 
Yes, you get a notice. You just don't have notices enabled in your error_reporting setting. RTFM.
 [2009-12-16 15:00 UTC] v dot srinath dot php at gmail dot com 
thanks.I am Newbie to PHP.

I turned on the error reporting engine and now I got the 'notice' reports. Here I assumed "s" as variable but it doesn't show any error.
So how "s" is considered here?
 
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