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Bug #44988 E_NOTICE error when referring to line
Submitted: 2008-05-13 22:55 UTC Modified: 2008-05-14 18:14 UTC
From: lgandras at hotmail dot com Assigned:
Status: Not a bug Package: Unknown/Other Function
PHP Version: 5.2.6 OS: *
Private report: No CVE-ID: None
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From: lgandras at hotmail dot com
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 [2008-05-13 22:55 UTC] lgandras at hotmail dot com 
Description:
------------
When error_reporting is set to E_ALL and a variable that is undefined is concatenated, the line of the E_NOTICE error is set to the last line of the concatenation.

Reproduce code:
---------------
<?php
error_reporting(E_ALL);
$undefined .= 
"some string";
?>

Expected result:
----------------
Notice: Undefined variable: undefined in C:\Documents and Settings\Andras Gyomrey\Mis documentos\www\error.php on line 3

Actual result:
--------------
Notice: Undefined variable: undefined in C:\Documents and Settings\Andras Gyomrey\Mis documentos\www\error.php on line 4

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 [2008-05-14 07:44 UTC] jani@php.net 
That's where the line begins. No bug here.
 [2008-05-14 18:14 UTC] lgandras at hotmail dot com 
I meant for example that if i put:

<?php
error_reporting(E_ALL);
$undefined .= 
"some".
"buggy ".
"string ";
?>

The message would say the line of the error would be the sixth  instead of the third. My problem came when i was looking for the "undefined" variable. It is right, that the value will be set, when the hole string is parsed. But I don't think that the common interest is where the string is completely parsed, but the line where the undefined variable resides.
 
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