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[2008-04-08 21:44 UTC] lagunaloire at argentina dot com
Description:
------------
The exec() function does not fill the &$output array!
I don't get the output from any program what I try to execute in Safe mode or not.
Reproduce code:
---------------
exec("program", $output);
print_r($output);
Expected result:
----------------
Array
(
[0] => line1
[1] => line2
[2] => line3
)
Actual result:
--------------
Array () sometimes or nothing at all.
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Last updated: Wed Feb 05 06:01:32 2025 UTC |
Not not! I mistake! I just put something in the array like this: $output=array("nothing here", "nothing there"); And I see that but that does not mean what I'm seing that from the program what I executed! Just I was seing it from the self php script. Sorry!! =S It is not working still! I don't get filled the array with the output for the external program.I found the problem. The problem is YOU CANNOT CALL exec() FROM A REQUIRED PHP. That mean if you require("somepage.php"); in somepage.php you cannot call exec();Newly. To call exec from "some.php" you cannot do a require in this manner: chdir("somedir"); require("some.php"); You must do it in this manner: require("somedir/some.php"); And exec() will work in "some.php".