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Bug #44486 dot syntax bug
Submitted: 2008-03-19 22:37 UTC Modified: 2008-03-20 02:31 UTC
Votes:1
Avg. Score:3.0 ± 0.0
Reproduced:1 of 1 (100.0%)
Same Version:1 (100.0%)
Same OS:1 (100.0%)
From: kowales at gmail dot com Assigned:
Status: Not a bug Package: Scripting Engine problem
PHP Version: 5.2.5 OS: Windows XP SP2
Private report: No CVE-ID: None
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From: kowales at gmail dot com
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 [2008-03-19 22:37 UTC] kowales at gmail dot com 
Description:
------------
I found error in join(dot) string syntax

Reproduce code:
---------------
//this works
<?php
$v1="blabla";
$tmp=(!empty($v1)) ? "," : "";
$v2.=$v1.$tmp;
print $v2;


//this should works
$v1="blabla";
$v2.=$v1.(!empty($v1)) ? "," : "";
print $v2;
?>

Expected result:
----------------
blabla,blabla,

Actual result:
--------------
,blabla,

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 [2008-03-20 02:31 UTC] felipe@php.net 
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

Hello,

$v2 .= $v1.(!empty($v1)) ? "," : ""; 
is equal
$v2 .= ($v1.(!empty($v1))) ? "," : "";

See the list precedence of operators, and the example about associativity in:
http://docs.php.net/manual/en/language.operators.php

$v2 .= $v1. (!empty($v1) ? "," : "");

It's the proper.
 
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