php.net |  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login

go to bug id or search bugs for

Request #35398 php's exec() requires a shell
Submitted: 2005-11-25 18:24 UTC Modified: 2015-01-09 00:00 UTC
Votes:1
Avg. Score:5.0 ± 0.0
Reproduced:1 of 1 (100.0%)
Same Version:0 (0.0%)
Same OS:1 (100.0%)
From: szo at szo dot hu Assigned:
Status: Wont fix Package: Program Execution
PHP Version: * OS: posix
Private report: No CVE-ID: None
View Developer Edit
Welcome back! If you're the original bug submitter, here's where you can edit the bug or add additional notes.
If you forgot your password, you can retrieve your password here.
Password:
Status:
Package:
Bug Type:
Summary:
From: szo at szo dot hu
New email:
PHP Version: OS:

 

 [2005-11-25 18:24 UTC] szo at szo dot hu 
Description:
------------
I use php in a chroot()-et environment, and I can't use exec()  unless I provide a shell in the chroot as well, which lowers it's security a bit. The exec() requires a shell because it's implemented using popen(). I think it should be possible to aboid popen and use dup() instead.

Patches

Pull Requests

History

AllCommentsChangesGit/SVN commitsRelated reports
 [2005-11-25 18:25 UTC] szo at szo dot hu 
changed os to posix
 [2015-01-08 23:59 UTC] ajf@php.net
-Status: Open +Status: Wont fix -Package: Feature/Change Request +Package: *General Issues -PHP Version: 5.1.0 +PHP Version: *
 [2015-01-08 23:59 UTC] ajf@php.net 
Can't be done, command arguments need to be parsed, sorry.
 [2015-01-08 23:59 UTC] ajf@php.net 
Or rather: exec() doesn't take an array of string arguments and a command name, it just takes a string containing a command line, so we need a shell to parse it.
 [2015-01-09 00:00 UTC] ajf@php.net
-Package: *General Issues +Package: Program Execution
 
PHP Copyright © 2001-2024 The PHP Group
All rights reserved. 		Last updated: Sat Dec 21 17:01:58 2024 UTC