Description:
------------
Something rather weird happens when you define a variable first as a string and then as an array. I am not sure whether this is actually a bug, or my failure to understand null-terminated strings. However, the effect is that the empty-string '' is evaluated as true. Sorry for wasting your time if this is spurious.

Reproduce code:
---------------
$foo[1]="x";
$foo=$foo[1];
$foo[2]='';

if ($foo[1]){
	echo "foo 1 is '$foo[1]' and is true<br>";
}

if ($foo[2]){
	#The value of $foo[2] printed here is \0. It evalutes as true, and is a 1-character length string.
	#This is DESPITE that fact that I just set it to be empty!
	echo "foo 2 is '$foo[2]' and is true<br>";
}


#A simpler case:
$bar="x";
$bar[2]='';
echo "bar 2 is '$bar[2]'<br>";


Expected result:
----------------
Not quite sure what to expect. But I do not expect the value of foo[2] which I just set to the empty string to evaluate as true!

I would expect only to see one line:

bar is ''






Actual result:
--------------
foo 1 is ' ' and is true
foo 2 is 'N' and is true
bar is 'N'


(I have used the character N to represent NUL, since
it would otherwise be invisible. Also note the space between
the quotes in the first line)