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Bug #3162 PHP4b3 - mysql_insert_id no longer accepts an arg
Submitted: 2000-01-10 14:40 UTC Modified: 2000-07-22 19:30 UTC
From: xmtj at rims dot com Assigned:
Status: Closed Package: MySQL related
PHP Version: 3.0.13 OS: RH Linux 6.1
Private report: No CVE-ID: None
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From: xmtj at rims dot com
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 [2000-01-10 14:40 UTC] xmtj at rims dot com 
$result = mysql_insert($query)
$id = mysql_insert_id($result)

This worked in PHP3. It fails in php4b3 with an error message:

PHP Warning:  Supplied argument is not a valid MySQL-Link resource in /home/httpd/html/yada.php

The solution:

$result = mysql_insert($query)
$id = mysql_insert_id()

Environment:

MySql: 3.22.27
PHP 4.03b

System: Linux rimsweb 2.2.12-20 #1 Mon Sep 27 10:25:54 EDT 1999 i586 unknown

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 [2000-07-22 19:30 UTC] mrobinso at cvs dot php dot net 
mysql_insert_id() accepts the link identifier, not
the result, as the parameter.

$conn = mysql_connect("yada","yada","yada");
... insert query ...;
$id = mysql_insert_id($conn);

If the link identifier is omitted, php assumes that
last valid link.
 
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