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Bug #31529 Can not escape Vars
Submitted: 2005-01-13 10:08 UTC Modified: 2005-01-14 10:17 UTC
From: david at 21stcd dot com Assigned:
Status: Not a bug Package: Scripting Engine problem
PHP Version: 4.3.8 OS: windows xp
Private report: No CVE-ID: None
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From: david at 21stcd dot com
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 [2005-01-13 10:08 UTC] david at 21stcd dot com 
Description:
------------
The problem comes from the use of var substitution or addtion to strings that you are trying to "escape"

I find this problem when trying to create escaped hex strings to write data to sockets.


Reproduce code:
---------------
<?PHP
$hex  = "FF";
echo "\x$hex";
?>

Expected result:
----------------
?

Actual result:
--------------
\xFF

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 [2005-01-14 04:46 UTC] sniper@php.net 
\x$ is not valid syntax.
 [2005-01-14 10:17 UTC] david at 21stcd dot com 
even so "\x".$hex

will not work either.

It was my understanding you could subsitiute vars into strings using the previous method I outline, where as the on I just outlined add the vars value onto the end of the string.
 
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