Description:
------------
Apologies if this isn't a bug.  Suspect it is an Apache problem.

I have Apache 1.3.33 and PHP 4.3.10 running on Windows XP Pro with Service Pack 2 installed.

I have retrieved a jpeg file into a php variable.  When trying to display the image i.e. echo("$pic"), the data of the jpeg rather than the jpeg itself is printed out.  Have used the sample code for "Creating a new GD image stream and outputting an image." in php manual and this does the same thing...display the image "data" rather than the image.  I have included header info ie content type = image/png or image/jpeg to with no luck.

I suspect it is a setting in Apache, but have trawled the internet and found many people with the same problem, but no-one has an answer.....can you help?

Reproduce code:
---------------
<?php
header("Content-type: image/png");
$im = @imagecreate(100, 50)
   or die("Cannot Initialize new GD image stream");
$background_color = imagecolorallocate($im, 255, 255, 255);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5,  "A Simple Text String", $text_color);
imagepng($im);
imagedestroy($im);
?> 

Expected result:
----------------
An image is drawn to screen

Actual result:
--------------
The following is displayed to screen...

?PNG  IHDRd2
????PLTE????[?˝?eIDATx?c` 
`fx???`? ????????   [vK????? ? ??\6p?)??u.``iP o9?٦?©Ty܍??㥀????X&Z?u Y?????IEND?B`?