Description:
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When sending the MySQL query through the mysql_query() function, MySQL does not send back a result set. But when echoing out the $sql statement and running it directly into the MySQL database via PHPMyAdmin or another tool, the query comes back with the intended results. Also, running a mysql_error(); outputs nothing. So this lead me to believe it was a bug in PHP.

Reproduce code:
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define("DB_ADDY","localhost");
define("DB_USER","icesnak_eqitems");
define("DB_PW","trademasters");
define("DB_DB","icesnak_eqitems");

function find_item($types,$terms){
	if((!empty($types))&&(!empty($terms))){
		$types[] = "stock";
		$terms[] = "instock";
		$dblink = mysql_connect(DB_ADDY,DB_USER,DB_PW);
		mysql_select_db(DB_DB,$dblink);
		$sql = "SELECT * FROM `items` WHERE `". $types[0]. "` LIKE '%". $terms[0]. "%' ORDER BY `itemname` ASC";
		$result = mysql_query($sql,$dblink);
		if(mysql_num_rows($result)){
			echo 'Something';
		} else {
			echo 'Nothing';
		}
	}
}

Expected result:
----------------
I would expect to get the output of "Something" since there are multiple rows in the database that match the search criteria. I think this issue has to do with the use of the "%" wildcard character...

Actual result:
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Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/mystuff/public_html/core/core/EQItems.php on line 73
Nothing