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[2004-06-21 19:35 UTC] nick dot rich at textmarketer dot co dot uk
Description:
------------
Trying to access a propery (via the get method) using a
value from another object as the method name fails.
See code::
if the line /// fails
is
replaced with
$localVar = $config->methodnames[1];
$test->$localVar
It works correctly
Reproduce code:
---------------
class config
{
public $methodnames = array("dog","cat");
}
class testClass
{
function Cat(){
echo "cat";
}
function Dog(){
echo "dog";
}
function __get($method){
eval("\$this->\$method();");
}
}
class main
{
function __construct(){
$config = new config();
$test = new testClass();
$test->$config->methodnames[1]; /// fails
}
}
$test = new main();
Expected result:
----------------
cat
Actual result:
--------------
Fatal error: Call to undefined method testClass::
Object() in /Users/nicholasrich/Sites/bits/
testclass.php(18) : eval()'d code on line 1
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Last updated: Thu Dec 26 11:01:30 2024 UTC |
The point is that the __get ihis being passed an object ref instead of the value. If you change the test class to: Class TestClass { private static $data = array("dog"=>"dog","cat"=>"cat"); function __get($value) { return self::$data[$value]; } } It will give the same resultThis is a bogus bug. The problem here is that you are trying to access properties in an improper way--pay attention to order of operations. The interpreter will operate from left to right--that is, on the line marked /// fails in the example code, it will first access $test, then call __get() with the value of (string) $config, which is 'Object'. You should have also gotten an error similar to: Notice: Object of class config to string conversion in C:\php5\test2.php on line 28 which shows that it is doing this cast to a string. you are expecting it to evaluate something like: $test->{$config->methodnames[1]}; when, in fact, php evaluates: {$test->$config}->methodnames[1]; which is not a bug.