Description:
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I used the MySql_Query with an argument put together as a string, part of it included the $_POST varible, and when passing the string to the MySql_Query I got no error, yet no resource id to use for the rest of my function.  I have tried to force the stringtype to the varible and that still didn't work. Keep in mind that the info stored in the $_POST is selected from a table in the db called "books".  Yet when I hard code the same format in the string it returns it.  Only get the problem when I use the varible.



Reproduce code:
---------------
<?php
if ($_POST != NULL) { 
echo "results for " . $_POST["Subject"];
$subject = $_POST["Subject"];
$qry = ("select * from " . $subject);
$sqlQry = (string) $qry;
GetVals();
}
function GetVals() {
$db = mysql_connect("localhost", "root");
mysql_select_db("books",$db);
$result = mysql_query($sqlQry);
echo $result;
}
?>

Expected result:
----------------
I expect it to echo the resource ID.  This was a test code I developed while debugging the rest of the project.  I leveled it down to this problem.  It's not allowing me to use any of the rest of the mysql functions because the resource id is non-existant.  I don't get errors until I try to use functions like MySql_fetch_row($result) and whatnot, and those errors say that the argument it invalid. 

Actual result:
--------------
null is stored in $result, leaving me high and dry for the rest of the project.