Description:
------------
When doing the following script it has a VERY weird behavior

As you might notice we did a =! instead of !=. It was an error, but we didn't notice.
Then we got the problem that it converted the content of the var to 1. So the value was now missing. It took us quite some time to debug on this one. Below is the script to reproduce the error. When running it, it might seems clearer what i mean




Reproduce code:
---------------
<?php

$aTest = array(
	'name' => 'And',
	'email' => 'test@test.com'
);
 echo "<pre>";
 print_r($aTest);
 
 if($aTest['name'] =! "") {
 
 	 print_r($aTest);
 
 }
  echo "</pre>";
 
?>


Expected result:
----------------
Parse error. Can't do a =!. Should be a !=

Actual result:
--------------
Array
(
    [name] => And
    [email] => test@test.com
)
Array
(
    [name] => 1
    [email] => test@test.com
)