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[2002-11-20 17:55 UTC] bmichael at goldparrot dot com
The variable reference is not working as I would understand it should. The example that follows is long, but just cut and paste then read the output.
Years of "C" programming says this should work.
Try example first then, look for the following lines in the
code:
//*****NOTE****JUST DELETE THE & symbol TO MAKE WORK
and remove the & symbol to see the correct output.
CODE STARTS HERE
**********************************************************
<?php
class A
{
var $name;
var $order;
}
class B
{
var $name;
var $list_array;
}
class C_LIST {
var $c_list;
function print_test($call,$cname)
{
// call: the variable you want to print_r
// cname: the label for your debugging output
echo $cname . ":<pre>";
print_r($call);
if ( is_array($call))
{
reset($call);
}
echo "</pre><hr>";
}
function test()
{
//new instantiated array in memory
$local_c_list = array();
//array indicies for
$i = 0;
$j = 0;
//array indicies for $x (see below)
$k = 0;
$x = array(0 => array(0 => "A_First", 1 => "B_First", 2 => 1),
1 => array(0 => "A_First", 1 => "B_Second", 2 => 2),
2 => array(0 => "A_First", 1 => "B_Third",2 => 3),
3 => array(0 => "A_Second",1 => "B_First",2 => 1),
4 => array(0 => "A_Second",1 => "B_Second",2 => 2),
5 => array(0 => "A_Second",1 => "B_Third",2 => 3)
);
//loop through in array of x, e.g. x[0][$l]
for ($k = 0; $k < 6; $k = $k + 1)
{
$b_name = $x[$k][0];
$a_name = $x[$k][1];
$a_order = $x[$k][2];
if ((!isset($b)) || (!isset($b->name)) || ($b_name != $b->name))
{
//attach the A record to the main list
// starting on the second A record found
if (isset($b->name))
{
//set the local_list to the reference of b
//this avoids memory copies
//*****NOTE****JUST DELETE THE & symbol TO MAKE WORK
$local_c_list[$i] = &$b;
$i = $i + 1;
$j = 0;
}
$b = new B();
$b->name = $b_name;
$b->list_array = array();
$this->print_test($b,"An element");
} //end if no B exists or we are beginning another B name
//Create new A record
$a = new A();
$a->name = $a_name;
$a->order = $a_order;
$this->print_test($a,"An item");
//Set $b->list_array[$a->order] = &$a -- the reference of $a
//*****NOTE****JUST DELETE THE & symbol TO MAKE WORK
$b->list_array[$j] = &$a;
$j = $j + 1;
$this->print_test($b,"A list");
} //end for k loops
$this->c_list = $local_c_list;
return;
} //end test
} //end class
$the_list = new C_LIST();
$the_list->test();
$the_list->print_test($the_list,"Test");
?>
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Last updated: Tue May 13 12:01:27 2025 UTC |
Also, please look at output from bottom up. This will make it easier to understand what is happening. If you want less output, just comment out the "print_test" functions. I am included the last set of lines from the output and have noted the differences between runs with ******** You will notice that in the proper code, the B_FIRST, B_SECOND and B_THIRD objects are stored properly. In the code using the & reference symbol, only the B_THIRD object is stored. It is stored three seperate times. The proper result should be : Test: c_list Object ( [c_list] => Array ( [0] => b Object ( [name] => A_First [list_array] => Array ( [0] => a Object ( ******** [name] => B_First [order] => 1 ) [1] => a Object ( ******** [name] => B_Second [order] => 2 ) [2] => a Object ( ******** [name] => B_Third [order] => 3 ) )))) Output from BAD calls using the & reference symbol will look like this: c_list Object ( [c_list] => Array ( [0] => b Object ( [name] => A_Second [list_array] => Array ( [0] => a Object ( ******** [name] => B_Third [order] => 3 ) [1] => a Object ( ******** [name] => B_Third [order] => 3 ) [2] => a Object ( ******** [name] => B_Third [order] => 3 ) )))) Hope this discussion is alieviates some of your time crunch. Thanks for those of us who depend on PHP for our businesses.