php.net |  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login

go to bug id or search bugs for

Bug #185 fputs puts wrong count when Backslash in string
Submitted: 1998-03-18 00:55 UTC Modified: 1998-03-28 14:32 UTC
From: philip at qs dot co dot nz Assigned:
Status: Closed Package: Other
PHP Version: 3.0b6 OS: Linx-ELF i586
Private report: No CVE-ID: None
View Developer Edit
Welcome back! If you're the original bug submitter, here's where you can edit the bug or add additional notes.
If you forgot your password, you can retrieve your password here.
Password:
Status:
Package:
Bug Type:
Summary:
From: philip at qs dot co dot nz
New email:
PHP Version: OS:

 

 [1998-03-18 00:55 UTC] philip at qs dot co dot nz 
If a backslash is in a string to fputs, then fputs adds an extra character
to the output stream for every backslash

for example:
  $ip="abc\def";
  fclose($fp);
  $fp = fopen("out","w+");
  $x=fputs($fp,"$ip");
  fclose($fp);

File out contains:

   61 62 63 5c 64 65 66 00
   a   b  c  \  d  e  f nul

The same result will be given for the string "abc\\def".

Patches

Pull Requests

History

AllCommentsChangesGit/SVN commitsRelated reports
 [1998-03-28 14:32 UTC] jim 
This is the correct behavior. As noted in the ChangeLog for 3.0b4, "\Z" (where Z
is not one of the usual escape characters) leaves the backslash intact (and generates
an error message at the E_NOTICE level, which isn't usually printed). Putting in a
double backslash simply escapes the backslash and gives the same output.
 
PHP Copyright © 2001-2024 The PHP Group
All rights reserved. 		Last updated: Sun Dec 22 04:01:29 2024 UTC