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Bug #12674 string +' true', types misunderstanding (?)
Submitted: 2001-08-09 08:18 UTC Modified: 2001-08-09 08:48 UTC
From: joustin at plusnet dot pl Assigned:
Status: Not a bug Package: Scripting Engine problem
PHP Version: 4.0.6 OS: Win2000 sp2
Private report: No CVE-ID: None
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From: joustin at plusnet dot pl
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 [2001-08-09 08:18 UTC] joustin at plusnet dot pl 
Hmm... why is that ?
Am I reading manual too briefly, or is there something with the operators ? might be bogus, but please enlighten me:P

btw: I thought that there's no seperate boolean type =]

<?
function foo(){
	return true;
}

if(foo() == 'whatever you like'){
	echo '!?!? why is that equal ?';
}
?>

<?
function paranoid(){
	return 1;
}

if(!(paranoid() == (string) 'whatever you like')){
	echo 'hmm??';
}
?>

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 [2001-08-09 08:32 UTC] alindeman@php.net 
any non-empty string will evaluate true!
 [2001-08-09 08:46 UTC] joustin at plusnet dot pl 
Geez... THAT'll make some people quite confused/lost, when analysing the results from a function with if/elseif or switch.

Consider:

<?
function foo(){
	#...
	return true;
	#...or...
	return 'works ok';
}

$foo = foo();
if(!$foo){
	#whatever
}elseif($foo == 'works ok'){
	#this will hit
}else{
	#or else...
}
?>
 [2001-08-09 08:48 UTC] joustin at plusnet dot pl 
I've come from perl, so it's quite easy for me to swallow that :) ... but others may stuck.

I suggest dropping a line about this one in the manual.. a workaround is to use '===' as the operator(PHP4) - of course as long as people would like to stuck to their current switch/if schemes.
 
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