Description:
------------
Using the references of function/method arguments of a specific type, I have the option to "throw" a variable of a specific type with a value of a different type than the specified one.
Sample scipt started by simply: "php test.php"

Test script:
---------------
<?php
function test_function(int &$variableByReference, $value)
{
    var_dump(['result 1 from inside test_function()' => $variableByReference]);
    $variableByReference = $value;
    var_dump(['result 2 from inside test_function()' => $variableByReference]);
}

$testVar1 = 234;
$testValue = 'cuckoo egg';
test_function($testVar1, $testValue);
var_dump(['result 3 from outside test_function()' => $testVar1]);



Expected result:
----------------
I expect, when set variable "$testValue = 'cuckoo egg';" and start script, to get an error message something like this: "Fatal error: Uncaught TypeError: Argument 1 passed to test_function() must be of the type int, string given".

This means the value of the variable is tested ONLY on SET value of reference, not RETURNED by reference value.

Actual result:
--------------
The script set anything to reference without testing return value (by reference).

$ php test.php 
array(1) {
  ["result 1 from inside test_function()"]=>
  int(234)
}
array(1) {
  ["result 2 from inside test_function()"]=>
  string(10) "cuckoo egg"
}
array(1) {
  ["result 3 from outside test_function()"]=>
  string(10) "cuckoo egg"
}