Because `($id === 0)` is evaluated as an expression before, meaning that essentially the `case` statement now looks like `case 1:`. The correct way to do that which you are trying to would be to make your case statement simply look like `case 0:`.

Please refer to the documentation int the future:
https://www.php.net/manual/en/control-structures.switch.php

Yes, I try it with "case 0:" , and the same issue is happening.

hell post the code you are actually using instead f**g decriptions ike " am not using the two cases in the same time" - switch works, full stop, echo what $id contains really at that moment

ok switch works so fine, you can test it if you are so sure and tell us the result, because when id in the array test contains 0, the $is =0, and even test it with var_dump, and gettype to be sure before post this, thank you.

I didn't understand that last part.

More useful for use would be a complete example that we could run that demonstrates your issue. The bug reporting form offers space for you to enter such a "test script". The code you have provided does not demonstrate your problem because if $id===0 then the second line of your code will cause "return 1;" to be evaluated and the switch will never even be reached.