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Bug #63920 imagejpeg
Submitted: 2013-01-06 17:04 UTC Modified: 2013-01-08 06:48 UTC
From: zebroid at list dot ru Assigned:
Status: Not a bug Package: GD related
PHP Version: 5.4.10 OS: debian 6.0
Private report: No CVE-ID: None
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From: zebroid at list dot ru
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 [2013-01-06 17:04 UTC] zebroid at list dot ru 
Description:
------------
after update php 5.3->php 5.4 i have a problem with image thumbnails in vbulletin forum v 3.8.7 (last in the 3.x branch)

after some investigations i find the problem. code
imagejpeg($image, '', $quality);
works fine in php 5.3 and output jpeg image to browser

but in php 5.4 in only generate error:
Warning: imagejpeg(): Filename cannot be empty in [path]/includes/class_image.php on line 1428

i read a documentation http://php.net/manual/en/function.imagejpeg.php and understand that now it should works maybe in more 'pedantic' way (imagejpeg($image, NULL, $quality)), but maybe for the Backward Compatible you make this function work in a old way? (NULL or '' in secord parameter to output jpeg)

or, at least, mention about that on http://php.net/manual/en/migration54.incompatible.php
vBulletin v3.x still rather popular and suppose that not only i may face this problem

(and sorry for my russian-english)

Test script:
---------------
imagejpeg($image, '', $quality); <-work in php 5.3, dont work in php 5.4

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 [2013-01-07 06:16 UTC] pajoye@php.net 
Thank you for this bug report. To properly diagnose the problem, we
need a short but complete example script to be able to reproduce
this bug ourselves. 

A proper reproducing script starts with <?php and ends with ?>,
is max. 10-20 lines long and does not require any external 
resources such as databases, etc. If the script requires a 
database to demonstrate the issue, please make sure it creates 
all necessary tables, stored procedures etc.

Please avoid embedding huge scripts into the report.
 [2013-01-07 06:16 UTC] pajoye@php.net
-Status: Open +Status: Feedback
 [2013-01-07 17:09 UTC] zebroid at list dot ru 
hm... well, it something like this

<?php

$jpeg_filename = "http://php.net/manual/en/images/21009b70229598c6a80eef8b45bf282b-imagecreatefromjpeg.jpg"; //or link to any local jpeg file
$jpeg_quality = 90;

$img = imagecreatefromjpeg($jpeg_filename);
header('Content-Type: image/jpeg');

//next line dont work in php 5.4, but work in php 5.3
imagejpeg($img, '', $jpeg_quality);

?>
 [2013-01-07 18:09 UTC] pajoye@php.net 
the "" is the problem I suppose, use NULL if you don't want to save it but output 
it directly.
 [2013-01-08 06:42 UTC] zebroid at list dot ru 
pajoye@php.net, can you read my first post at 2013-01-06 17:04 UTC?
 [2013-01-08 06:48 UTC] pajoye@php.net
-Status: Feedback +Status: Not a bug
 [2013-01-08 06:48 UTC] pajoye@php.net 
We can't change that. It is part of the parameter parsing API. Simply use NULL 
which is actually what should have been used.
 [2015-06-10 17:01 UTC] gnikoloudis dot com at gmail dot com 
Thanks for the feedback and resolution
 
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