php.net |  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login

go to bug id or search bugs for

Bug #60697 gettype() cann't distinguish object and function?
Submitted: 2012-01-10 05:25 UTC Modified: 2012-01-10 08:44 UTC
Votes:3
Avg. Score:3.0 ± 0.0
Reproduced:3 of 3 (100.0%)
Same Version:3 (100.0%)
Same OS:3 (100.0%)
From: hfcorriez at gmail dot com Assigned:
Status: Not a bug Package: Scripting Engine problem
PHP Version: 5.3.8 OS: all
Private report: No CVE-ID: None
View Developer Edit
Welcome! If you don't have a Git account, you can't do anything here.
If you reported this bug, you can edit this bug over here.
(description)
Block user comment
Status: Assign to:
Package:
Bug Type:
Summary:
From: hfcorriez at gmail dot com
New email:
PHP Version: OS:

 

 [2012-01-10 05:25 UTC] hfcorriez at gmail dot com 
Description:
------------
I create a lambda function with a variable, then check it type with gettype , it's 
return "object", It think it's not good in here.

Test script:
---------------
$a = function(){}; 
$b = new stdClass();
echo gettype($a) . '|' . gettype($b); // echo 'object|object'

Patches

Pull Requests

History

AllCommentsChangesGit/SVN commitsRelated reports
 [2012-01-10 08:20 UTC] cataphract@php.net 
"function" is not a type. See http://php.net/manual/en/language.types.php
 [2012-01-10 08:20 UTC] cataphract@php.net
-Status: Open +Status: Bogus
 [2012-01-10 08:44 UTC] hfcorriez at gmail dot com 
I think it's not good for use
When I want to check function and call witch $a(), I must check it's a object and 
the class name is "Closure"
 [2012-08-15 03:30 UTC] a at b dot c dot de 
If you want to tell if something is a function (i.e. callable), use is_callable(). If you want to tell if something is an object and callable, use is_object and is_callable().
 
PHP Copyright © 2001-2025 The PHP Group
All rights reserved. 		Last updated: Sun Jul 13 23:01:33 2025 UTC