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[2000-08-10 08:52 UTC] bmcadams@php.net
[2000-08-11 20:50 UTC] bmcadams@php.net
[2000-08-12 04:10 UTC] bmcadams@php.net
[2000-09-03 19:38 UTC] sniper@php.net
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Last updated: Mon Jun 29 08:00:02 2026 UTC |
Hi... I have php4.01pl2 running on Redhat 6.2. I start querrying Databases like this. $link = mysql_connect($_Server,$_User,$_Spasswort); @mysql_select_db($_Database,$link); $result = mysql_fetch_array(mysql_query("select * from User where UID = '$TransID' and UsrTemp ='1' ")); The mysql_fetch_array works fine and all values are returned. But if i make this at next. $tempo = mysql_query("update User set UsrTemp='0' where UID = '$TransID' "); This error appears: Warning: MySQL: Unable to save result set in /www/httpd/foo.de/html/paygate/successcc.phtml on line 24 But the querry does in the Database what it has to do so there should no error be returned. The querry works but the errormessage comes. So what to do to fix this? Regards Alex