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Bug #51013 use namespace in eval
Submitted: 2010-02-11 11:53 UTC Modified: 2010-02-11 13:21 UTC
Votes:3
Avg. Score:4.7 ± 0.5
Reproduced:2 of 2 (100.0%)
Same Version:2 (100.0%)
Same OS:2 (100.0%)
From: dellytufy at hotmail dot com Assigned:
Status: Not a bug Package: Unknown/Other Function
PHP Version: 5.3SVN-2010-02-11 (SVN) OS: win
Private report: No CVE-ID: None
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From: dellytufy at hotmail dot com
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 [2010-02-11 11:53 UTC] dellytufy at hotmail dot com
Description:
------------
i cannot use namespace in eval() 
as
eval('use namespaceName\classname as  myClass;');

after this  i cannot ust  $mc=myClass();  undeclared class

namespace d3;
    namespace d3\sql;
        class oracle{
             public $type='oracle';
        } 

         
       namespace d3\linq;
       class linq{
           public $className='linq';
       }


$type='oracle';    
   eval('use \d3\sql\\'.$type.' as baglanti;');
   $a=new baglanti();// error. undeclared class  d3\linq\baglanti
   echo $a->type; 

Reproduce code:
---------------
$type='oracle';    
   eval('use \d3\sql\\'.$type.' as baglanti; $a=new baglanti();');
   echo $a->type; 

but this is successfully runned.

Expected result:
----------------
namespace d3;
    namespace d3\sql;
        class oracle{
             public $type='oracle';
        } 

         
       namespace d3\linq;
       class linq{
           public $className='linq';
       }


$type='oracle';    
   eval('use \d3\sql\\'.$type.' as baglanti;');
$a=new baglanti();
  echo $a->type; 

i think it must write oracle .


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 [2010-02-11 12:11 UTC] johannes@php.net
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

The use in the eval() is valid for the eval\'d code.
 [2010-02-11 13:21 UTC] dellytufy at hotmail dot com
thanx i will check again

but 

why  it's running 
eval('use \d3\sql\\'.$type.' as baglanti; $a=new baglanti();');


it's not
eval('use \d3\sql\\'.$type.' as baglanti;');
 
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