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Bug #35545 Bug with some syntaxes in for loops
Submitted: 2005-12-04 13:04 UTC Modified: 2005-12-04 14:28 UTC
From: kervala at jpopdb dot net Assigned:
Status: Not a bug Package: Variables related
PHP Version: 5.1.1 OS: Linux 2.4
Private report: No CVE-ID: None
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From: kervala at jpopdb dot net
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 [2005-12-04 13:04 UTC] kervala at jpopdb dot net 
Description:
------------
For my site, I used a piece of code which always worked fine. (see below)

It's a simple PHP code using a "for" loop and variables manipulation.


Reproduce code:
---------------
for($i=date("Y")+1; $i>=1970; $years[$i] = $i--);
	
print_r($years);


Expected result:
----------------
In all previous PHP versions, it returned :

2006 => 2006,
2005 => 2005,
etc...


Actual result:
--------------
It now returns :

2005 => 2006,
2004 => 2005,
etc...

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 [2005-12-04 13:14 UTC] tony2001@php.net 
The result of this code is unknown in all languages: 
$years[$i] = $i--;
 [2005-12-04 13:38 UTC] kervala at jpopdb dot net 
If $i is set to 200:

$years[$i] = $i--;
=> "$years[200] = 200;" not "$years[200] = 199;"

I don't see where the code is unknown... It's valid in all languages...

By the way why this code always worked in previous versions if this is unknown code ? ;p

I suppose it's a regression.
 [2005-12-04 14:28 UTC] kervala at jpopdb dot net 
Oops, sorry, tou didn't meant that's the code which was unknown but the result...

However, I always knew that the 3rd parameter of "for" were instructions and the return code wasn't used even if "$years[$i] = $i--" should return $i in my case.
 
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