Description:
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If you look at the code I initialize a 32bit hex value and print it with both printf and echo.  I do a AND and a OR to get the value back to the original value and print it again with printf and echo.

Printf and echo disaggree on the first print
Printf and echo agree on the second print
Printf and echo agree on the third print.

What happened with the first print?
I realize you use signed integers.....but where is my sign?


Reproduce code:
---------------
<?
$a = 0x8000000F;
printf("hex=%x, dec=%d by printf\n",$a,$a);
echo $a."by echo\n";
$a = $a & 0x0FFFFFFF;
printf("hex=%x, dec=%d by printf\n",$a,$a);
echo $a."\n";
$a = $a | 0x80000000;
printf("hex=%x, dec=%d by printf\n",$a,$a);
echo $a."\n";
?>


Expected result:
----------------
I expect both printf and echo to consistantly print out the same decimal result.

Actual result:
--------------
The first time they didnt and second time they did.