Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

dbase_get_record*() funcs return a row and add "deleted" field to indicate if this row were marked for deletion or not.
You can see a note about it in dbase_replace_record() reference:
"Note: If you're using dbase_get_record() return value for this parameter, remember to reset the key named deleted."

Also, dbase_replace/add_record() work only with indexed arrays and this is documented too.

Thanks Tony2001 in advance.

If I understood the explanation, it means that I should use dbase_get_record() instead of dbase_get_record_with_names() as it is in the "Example 438. Updating a record in the database" in the section "Function Reference / dBase Functions".

I tried again as the PHP Manual Example with some changes :
1. dbase_get_record instead of dbase_get_record_with_names
2. '0' for 'date'

Even then, the get_record followed by replace_record did not works as it should.
The 'dbase_get_record()' gave me an indexed array, but the same error occurs :
PHP Warning:  dbase_replace_record(): unexpected error in D:\Apache\Apache2\htdocs\tests\_debug_tmp.php on line 17

No problem, I created a function to execute the replace that recreates an indexed array and take the extra 'deleted' element off.
$rarr = array();
foreach ($row as $i => $vl) { if ($i <> "deleted") { $rarr[] = $vl; } }

I believe that this transformation should be inside the dbase_replace_record, and not so simple like mine, but considering the table structure crossed with the array elements.

Best Regards,

Sorry, the correct example should be :

unset($row['deleted']);
$rarr = array();
foreach ($row as $i => $vl) { $rarr[] = $vl; }

and then replace_record using rarr.