Description:
------------
I'm using MySQL 4.1.3-beta

For me the mysqli functions work.
There's just a different behavior I found between PHP 5.0.0 and PHP 5.0.1 in function mysqli_fetch_array

Example:
--------
SQL-Statement: SHOW TABLES FROM databasename

mysqli_fetch_array (PHP 5.0.0) returns:
[0] = tablename

mysqli_fetch_array (PHP 5.0.1) returns:
[Tables_in_databasename] = tablename

PHP crash with "exit signal Segmentation fault (11)" when I try mysqli->query
For example this script doesn`t work
<?php
	$db_host = "127.0.0.1";
	$db_user = "test";
	$db_pass = "test123";
	$db_name = "test";

	$db = new mysqli($db_host, $db_user, $db_pass, $db_name);

	$num = $db->query("SELECT uid FROM test WHERE flag = 'TRUE'")->num_rows;
	echo "$num flags<br>";

	$db->close();
	echo "ok<br>";
?>

But this script is work

<?php
	$db_host = "127.0.0.1";
	$db_user = "test";
	$db_pass = "test123";
	$db_name = "test";

	$db = mysqli_connect($db_host, $db_user, $db_pass, $db_name);

	$res = mysqli_query($db, "SELECT uid FROM test WHERE flag = 'TRUE'");
	$num = mysqli_num_rows($res);

	echo "$num flags<br>";

	echo "ok<br>";
?>

I`m using php 5.0.1, mysql 4.1.3-beta, FreeBSD 5.1

I'm experiencing a similar problem regarding MySQLi (4.1.3) and PHP 5.0.1:

$res = $mymysqliobject->query("select * from table") works just fine but $res->num_rows crashes PHP (segfault, apache reports signal 11).

It is reproducible by using the demo script given at http://www.zend.com/php5/articles/php5-mysqli2.php and replacing the line "var_dump($result->fetch_row());" by "echo $result->num_rows;".

Sorry, but your problem does not imply a bug in PHP itself.  For a
list of more appropriate places to ask for help using PHP, please
visit http://www.php.net/support.php as this bug system is not the
appropriate forum for asking support questions. 

Thank you for your interest in PHP.