|
php.net | support | documentation | report a bug | advanced search | search howto | statistics | random bug | login |
[2004-02-15 21:06 UTC] lingwitt at bellsouth dot net
Description:
------------
When an object's method calls upon another one of its
methods such that the second method returns a reference
that is stored in the the first method as a local
variable, then the reference persists in some way so as
to make cloning problematic.
As a result, a modification to the referenced variable
in the clone cuases a modification to the same variable
in original.
Reproduce code:
---------------
class A
{
var $a = array();
public function makeAReference()
{
$array = $this->getA();
}
public function &getA()
{
return $this->a;
}
}
$A = new A;
$A->a = array(1);
$A->makeAReference();
$clone = clone $A;
$clone->a = array();
print_r($A);
Expected result:
----------------
This is gotten when $A->makeAReference() is removed.
A Object
(
[a] => Array
(
[0] => 1
)
)
Actual result:
--------------
Obviously the modification made it back to the original.
A Object
(
[a] => Array
(
)
)
PatchesPull RequestsHistoryAllCommentsChangesGit/SVN commits
|
|||||||||||||||||||||||||||||||||||||
Copyright © 2001-2025 The PHP GroupAll rights reserved. |
Last updated: Mon Oct 27 14:00:01 2025 UTC |
In fact, the reference doesn't need to be made in a method: class A { var $a = array(); public function &getA() { return $this->a; } } $A = new A; $A->a = array(1); $array = $A->getA(); $clone = clone $A; $clone->a = array(); print_r($A);