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Bug #24367 strspn('rRc', 'R') returns 0
Submitted: 2003-06-27 15:21 UTC Modified: 2003-06-30 04:51 UTC
From: php at projectjj dot com Assigned:
Status: Not a bug Package: Strings related
PHP Version: 4.3.2 OS: Windows 2k SP3
Private report: No CVE-ID: None
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 [2003-06-27 15:21 UTC] php at projectjj dot com 
Description:
------------
echo strspn('rRc', 'R'); // returns 0
echo strspn('Rrc', 'R'); // returns 1

Shouldn't both of these return 1?

Reproduce code:
---------------
echo strspn('rRc', 'R');

Expected result:
----------------
1

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 [2003-06-27 17:36 UTC] marcot at tabini dot ca 
No, because strspn is case-sensitive. In the first instance, there is no initial string that contains characters from your second parameter (the string begins with 'r', which doesn't match any of the characters in 'R'). In the second case, the first character of 'Rrc' contains characters from 'R', and therefore the function returns 1.
 [2003-06-27 17:45 UTC] sniper@php.net 
It works exactly the same as the libc counterpart,
that's the expected way. Not bug.
 [2003-06-27 19:05 UTC] php at projectjj dot com 
I did expect it to be case-sensitive, but by your description that means it will only search from the start of the string.
A matching substring does not count.

From the manual:
"strspn --  Find length of initial segment matching mask"
The use of 'segment' made me think otherwise.

Perhaps a re-wording is needed...
 [2003-06-30 04:51 UTC] mgf@php.net 
What about "initial segment" do you find unclear?  Why would you think the use of "segment" in any way contradicts the use of "initial"?  I cannot think of any way of rewording this that would be appreciably clearer.
 
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