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[2003-03-17 11:33 UTC] eric at evilwalrus dot com
If I have the following script, the class that is defined before the namespace cannot be called from within a class in the namespace.
<?php
class TestClass2
{
function __construct()
{
print "TestClass2\n";
}
}
namespace Test
{
function newClass () {
$new = new TestClass();
$new->newClass();
}
class TestClass
{
function __construct()
{
print "TestClass\n";
}
function newClass ()
{
$new = new TestClass2();
}
}
}
Test::newClass();
//$new = new TestClass2();
?>
This example will show the error "Fatal error: Class 'testclass2' not found in c:\usr\test.php on line 26" I'm assuming that this is done by design... but I would think that PHP would look for the class outside of the namespace since it is defined before the namespace. If you use the commented out line $new = new TestClass2; instead of the Test::newClass(); then it works properly, and the TestClass2 construct is called.
As I said, I think this is done by design and isn't a bug... but I thought I would submit it because I'm not for sure. Any explination though would be very helpful to me. Thanks.
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Last updated: Mon Oct 27 17:00:01 2025 UTC |
Also pretty annoying if you want to declare a class extending the main exception class in your namespace. It simply doesn't work because its not "seen": $ php -r 'class myexception extends exception { } ' [no error, works] $ php -r 'namespace myscope { class myexception extends exception { } }' Command line code(1) : Fatal error - Class 'exception' not found I couldn't find a way to reference the global namespace.Thanks to Marcus who brought light into this: You access classes from the global namespace by ommiting the namespace-name part: new ::TestClass2(); is the proper syntax. Same for my exception extending problem: php -r 'namespace myscope { class myexception extends ::exception { } }' Marking as a documentation problem (it's not in ZEND_CHANGES even).