Hi,
I have a problem with FTP Fileupload. 
if i execute the script i receive this message

'Warning: error opening C:\Images\any.jpg in ftp.php on line 90'

the ENCTYPE in form-tag is "multipart/form-data". Method is Get. I receive the right Path information but it seems that the file couldn 't be opened. File Upload is activated. The MaxFilesize is 20MB. I don't know what it could be.

Ah, one thing: I must replace '\\' through '\' because the path which is returned from the file-element is 'C:\\Images\\any.jpg'

Can you help me???

Thanks
Tornby

Sorry for my bad english

info:
[phpcut] opens the Sourcecode cut and [/phpcut] ends it.

[phpcut]

$connection = ftp_connect(FTP_host);
    $login = ftp_login($connection, FTP_uid, FTP_pwd);
    ftp_pasv($connection,true);

    $iPos = 0;
    $FTPError = "";
    
    while ($iPos < 10)
    {
      If (!empty($HTTP_GET_VARS['file'.$iPos]))
      {
        $SourceFile = str_replace('\\\\','\\',$HTTP_GET_VARS['file'.$iPos]);
        $DestinationFile = $destination.Substr($SourceFile,strrpos($SourceFile,'\\')+1,strlen($SourceFile)-strrpos($SourceFile,'\\')-1);
        if (! ftp_put($connection,$DestinationFile,$SourceFile,FTP_BINARY)) $FTPError .= "Fehler beim hochladen von '$SourceFile'<br>";
      }
      $iPos++;
    }

    ftp_quit($connection);

[/phpcut]