I am using Windows XP, PHP 4.2.3, Apache 1.3.26

I am using XSLT to produce HTML output. The code I use is as follows:

$arg_buffer = array("/xml" => $xml_string, "/xslt" => $xsl_string);
$result = xslt_process($xp, "arg:/xml", "arg:/xslt", NULL, $arg_buffer, $params)))

My xsl file contains as 'include' statement which points to a file which exists in the same folder as the PHP script.

I initially tried it as <xsl:include href="pagination.xsl"/> but it produced this error:

'arg:/pagination.xsl' not found (error code: 65)

I then tried it with <xsl:include href="file://pagination.xsl"/> and got this error:

cannot open file '/pagination.xsl' (error code: 4)

It only works if I enter the full path, as in <xsl:include href="file://c:/blah/blah/blah/pagination.xsl"/>

It is very inconvenient to have to specify the full pathname in every <xsl:include> statement. Should it not first look in the current directory?

This may be more of an enhancement request than a bug.