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Bug #14774 strpos with strtolower to working incorrectly
Submitted: 2001-12-30 10:45 UTC Modified: 2001-12-30 17:59 UTC
From: armtuk at yahoo dot com Assigned:
Status: Not a bug Package: Strings related
PHP Version: 4.0.6 OS: Linux 2.4.9-7smp
Private report: No CVE-ID: None
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From: armtuk at yahoo dot com
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 [2001-12-30 10:45 UTC] armtuk at yahoo dot com 
<?php

$query="insert into users (user_name) values 'user_name'";

if (strpos(strtolower($query),"select")==0)
{
   print "FISH!";
}

?>

Amazingly enough this prints FISH!.

but:

$query="insert into users (user_name) values 'user_name'";

if 
(strpos(strtolower($query),"select")==0&&!(strpos(strtolower($query,"select")===FALSE))
{
   print "FISH!";
}

does not.

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 [2001-12-30 10:50 UTC] mfischer@php.net 
Thats the documented and expected behaviour.
 [2001-12-30 10:54 UTC] georg@php.net 
Sorry, but it works correct.

In your sample $query has no "insert", therefore strpos 
returns 0 (not found), as desribed in the manual.
 [2013-06-29 02:10 UTC] aledmb at gmail dot com 
strpos has a bug.

the following statement should give 1, but gives zero:

echo strpos(strtolower('C'), 'c');
 [2013-06-29 02:15 UTC] aledmb at gmail dot com 
please ignore my previous comment, i'm dumb... should be checking for false, as 
zero is a valid offset.
 
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