Small bugs?I don't know.

<?php
  $value = @ (2 / 0);
?>

From browser Ouput :
<br />
<b>Warning</b>:  Division by zero in <b>Unknown</b> on line <b>0</b><br
/>

But From Zend Studio's "GO" (X-Powered-By: PHP/4.3.2) , Output is nothing...

The correct is nothing output .

Please try using this CVS snapshot:

  http://snaps.php.net/php4-STABLE-latest.tar.gz
 
For Windows:
 
  http://snaps.php.net/win32/php4-win32-STABLE-latest.zip

The same ....... 
I thank it is different between 4.3.4(or higher) and 4.3.3 .
Or it is different between IIS and Apache .
I haven't tested On IIS/php4.3.4 , but I tested the code on IIS/4.3.3 , everything is OK.

The Error process have something wrong :

-------------------------------------------
<?
error_reporting( E_ALL ^ E_NOTICE  );		//  ???þ??漶??
function myErrorHandler ($errno, $errstr, $errfile, $errline) {
		switch ($errno)
		{
			case E_USER_NOTICE:
			case E_USER_WARNING:
			case E_NOTICE:
			case E_CORE_WARNING:
			case E_CORE_ERROR:
			case E_COMPILE_WARNING:
				break;
			default:
				die("here");
		}
  }
$old_error_handler = set_error_handler("myErrorHandler");
//	mysql_connect ("localhost", "username", "secret");
        
     $ubirth="";
     $arr=explode("-", $ubirth);
     print_r($arr);
     list($year, $month, $day) = explode("-", $ubirth);
    echo checkdate($month, $day, $year);
	echo checkdate(1, 1, 1);
    exit;

?>
---------------------------------------
On IIS5/PHP4.3.3 everything is OK . Output is "Array ( [0] => ) 1"
On Apache2/PHP4.3.4(4.3.5RC4-dev) . Output is "Array ( [0] => ) here".


I don't know why it is different . but it makes me puzzle .

emm.....the logs is:
checkdate() expects parameter 3 to be long, string given
(PHP 4.3.4 or higher / Apache2.0.48 / Windows Server 2003)

This is not a bug, check_date() gives an E_WARNING error since PHP 4.3.4 in case the parameter passed is not an integer. Because you explode on a string, the first ($year) will contain the string and both $month and $day will contain NULL, which are automatically converted to '0', but the empty string for $year isn't.

This also has nothing to do with your earlier example:
<?php echo @ (2/0); ?> shows no output at all on php 4.3.2, 4.3.3, 4.3.5rc1 and 5.0dev

Sorry . My English is not good :(
But , 

<?php

$value = @ (2/0);

?>

On PHP4.3.4(or higher) , the output is :

Warning: Division by zero in Unknown on line 0

Not:

This also has nothing to do with your earlier example:
<?php echo @ (2/0); ?> shows no output at all on php 4.3.2, 4.3.3,4.3.5rc1 and 5.0dev

derick@kossu:~$ php-4.3.5RC3 -n -derror_reporting=2047 -r '$value = @ (2/0);';
derick@kossu:~$ php-5.0dev -n -derror_reporting=2047 -r '$value = @ (2/0);';
derick@kossu:~$


no output...

Oh~My God ! Look At These two Pictures :
http://www.openphp.cn/zero.gif
http://www.openphp.cn/zero2.gif
I don't know how to use CMD ....:)

OK,$value = @ (2/0); has always output .  On Windows Server 2003 . Some One test it ?

http://www.openphp.cn/zero.gif
http://www.openphp.cn/zero2.gif