| Bug #49939 | iconv_substr() misbehaves when length parameter set to 0 | ||||
|---|---|---|---|---|---|
| Submitted: | 21 Oct 8:32am UTC | Modified: | 13 Nov 7:48pm UTC | ||
| From: | ladislav at marek dot su | Assigned to: | |||
| Status: | Closed | Category: | Documentation problem | ||
| Version: | 5.*, 6 | OS: | * | ||
[21 Oct 10:24am UTC] jani@php.net
It's just a bug in the docs. iconv_substr() behaves exactly same way as substr() does with same parameters.
[13 Nov 7:48pm UTC] svn@php.net
Automatic comment from SVN on behalf of vrana Revision: http://svn.php.net/viewvc/?view=revision&revision=290687 Log: Length default (bug #49939)
[13 Nov 7:48pm UTC] vrana@php.net
This bug has been fixed in the documentation's XML sources. Since the online and downloadable versions of the documentation need some time to get updated, we would like to ask you to be a bit patient. Thank you for the report, and for helping us make our documentation better. Default is strlen($str).
Description: ------------ According to documentation and reflection: iconv_substr has third argument $length, default value is 0, but iconv_substr returns different result when argument is not passed and when argument is passed as zero. (Now it's not possible to call iconv_substr with $charset argument and preserve correct behaviour.) Reproduce code: --------------- var_dump(iconv_substr('foobar', 3)); // "bar" var_dump(iconv_substr('foobar', 3, 0)); // "" var_dump(iconv_substr('foobar', 3, NULL, 'UTF-8')); // "" Expected result: ---------------- string(3) "bar" string(0) "bar" string(0) "bar" Actual result: -------------- string(3) "bar" string(0) "" string(0) ""