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Doc Bug #43789 Missing information about preg_replace() returning null
Submitted: 2008-01-08 22:22 UTC Modified: 2008-01-09 00:17 UTC
From: david at dfoerster dot de Assigned:
Status: Closed Package: Documentation problem
PHP Version: Irrelevant OS: Linux
Private report: No CVE-ID: None
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From: david at dfoerster dot de
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 [2008-01-08 22:22 UTC] david at dfoerster dot de 
Description:
------------
I just filled a bogus bug report about preg_replace() returning 
null. (http://bugs.php.net/bug.php?id=43788) I guess this was 
introduced with preg_last_error in PHP 5.2 and should be documented.

I guess this applies to other preg_* functions as well.

Reproduce code:
---------------
Read the online documentation to preg_replace.

Expected result:
----------------
Return Values
preg_replace() returns an array if the subject parameter is an 
array, or a string otherwise. 
 If matches are found, the new subject will be returned, otherwise 
subject will be returned unchanged. If an error occurs, null (or 
false ?) will be returned and the error will be available through 
preg_last_error().

Actual result:
--------------
Return Values
preg_replace() returns an array if the subject parameter is an 
array, or a string otherwise. 
 If matches are found, the new subject will be returned, otherwise 
subject will be returned unchanged.

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History

AllCommentsChangesGit/SVN commitsRelated reports
 [2008-01-09 00:17 UTC] felipe@php.net 
This bug has been fixed in the documentation's XML sources. Since the
online and downloadable versions of the documentation need some time
to get updated, we would like to ask you to be a bit patient.

Thank you for the report, and for helping us make our documentation better.
 
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