Description:
------------
When using foreach to iterate over an array using the reference (&$value) syntax, and using foreach a second time using the same variable name changes the original array by overwriting the array's last item with the second-last.

This is obviously wrong...


Hint: note the missing object's id #4 in the actual result

Test script:
---------------
// the example uses objects to show the object's id in the output, but this error also occurs works with scalars

class A {}

$c = array(new A(), new A(), new A(), new A());
$arr = $c; // to keep the reference

var_dump($arr);

foreach ($arr as &$value) {}
	
var_dump($arr);

// using the same variable name
foreach ($arr as $value) {}

var_dump($arr);

Expected result:
----------------
array(4) {
  [0]=>
  object(A)#1 (0) {
  }
  [1]=>
  object(A)#2 (0) {
  }
  [2]=>
  object(A)#3 (0) {
  }
  [3]=>
  object(A)#4 (0) {
  }
}
array(4) {
  [0]=>
  object(A)#1 (0) {
  }
  [1]=>
  object(A)#2 (0) {
  }
  [2]=>
  object(A)#3 (0) {
  }
  [3]=>
  object(A)#4 (0) {
  }
}
array(4) {
  [0]=>
  object(A)#1 (0) {
  }
  [1]=>
  object(A)#2 (0) {
  }
  [2]=>
  object(A)#3 (0) {
  }
  [3]=>
  object(A)#4 (0) {
  }
}


Actual result:
--------------
array(4) {
  [0]=>
  object(A)#1 (0) {
  }
  [1]=>
  object(A)#2 (0) {
  }
  [2]=>
  object(A)#3 (0) {
  }
  [3]=>
  object(A)#4 (0) {
  }
}
array(4) {
  [0]=>
  object(A)#1 (0) {
  }
  [1]=>
  object(A)#2 (0) {
  }
  [2]=>
  object(A)#3 (0) {
  }
  [3]=>
  &object(A)#4 (0) {
  }
}
array(4) {
  [0]=>
  object(A)#1 (0) {
  }
  [1]=>
  object(A)#2 (0) {
  }
  [2]=>
  object(A)#3 (0) {
  }
  [3]=>
  &object(A)#3 (0) {
  }
}