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Bug #52643 No error/warning for data after missing semicolon after break statement
Submitted: 2010-08-19 10:42 UTC Modified: 2010-08-20 07:22 UTC
From: haakon dot nessjoen at gmail dot com Assigned:
Status: Not a bug Package: Scripting Engine problem
PHP Version: 5.2.14 OS: Linux
Private report: No CVE-ID: None
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From: haakon dot nessjoen at gmail dot com
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 [2010-08-19 10:42 UTC] haakon dot nessjoen at gmail dot com
Description:
------------
If you forget the semicolon after a 'break' statement. Almost all characters up to the next ; is ignored. Hence you won't get a error message about the problem.

For example, if you set a variable immediately after a mistake like this. You might be wondering for a long time of why the variable is not set.

Test script:
---------------
<?

if (0)
 break

$variable1 = 'hey';
$variable2 = 'ho';

print "Variable1 = $variable1\n";
print "Variable2 = $variable2\n";

?>

Expected result:
----------------
Error message

Actual result:
--------------
Variable1 = 
Variable2 = ho

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 [2010-08-19 18:28 UTC] johannes@php.net
break may have a parameter. In your case it is the return value of $variable1 = 'hey'; which is the string 'hey'
 [2010-08-20 07:22 UTC] aharvey@php.net
-Status: Open +Status: Bogus
 [2010-08-20 07:22 UTC] aharvey@php.net
I suspect Johannes meant to close this. :)
 
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