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Bug #8582 normal if nested in alternate if gives parse error
Submitted: 2001-01-07 20:09 UTC Modified: 2001-01-08 06:53 UTC
From: wojas at vvtp dot nl Assigned:
Status: Closed Package: Scripting Engine problem
PHP Version: 4.0.3pl1 OS: Linux
Private report: No CVE-ID: None
View Developer Edit
 [2001-01-07 20:09 UTC] wojas at vvtp dot nl 
The following php code gives a parse error at the 'else:'

<?php
if(1==1):
        echo "ok so far<p>";
        if(1==1) echo "error here!";
else:
        echo "Not possible";
endif;
?>

It looks like php thinks the 'else:' is part of the second 
if construct; the following code works:

<?php
if(1==1):
        echo "ok so far<p>";
        if(1==1) echo "error here!";
        echo "void";
else:
        echo "Not possible";
endif;
?>

Tested with 4.0.3pl1, 4.0.4RC3 and 3.0.18 on debian woody and potato.

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 [2001-01-08 06:53 UTC] stas@php.net 
Indeed the parser thinks else is a part of second construct
and chokes on ":". I'd suggest first to switch to newer {}
syntax, and then bracket your ifs so that you are sure you
and the parser agree on what is the part of what.
 
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